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Super Member
Re: Diluting chemicals
You have to use the -log to get a positive value for that part of the equation. The log(1/11) = -1.04139. The -log(1/11) = 1.04139.
9 - 1.04139 = 7.95861.
If you are starting with an acid, you still have to use the -log. The formula for an acid is original chemical pH + (-log(original volume/new volume)).
Diluting the acid will increase the pH and bring it closer to 7. Pure water has a pH value of 7.
Lemon juice has a pH of 3. Diluting it 10:1 will yield:
3 + (-log(1/11)) = 4.04139
I believe in treating everybody with respect, and clean cars. That’s what I believe in.
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Super Member
Re: Diluting chemicals
Originally Posted by
UncleDavy
You have to use the -log to get a positive value for that part of the equation. The log(1/11) = -1.04139. The -log(1/11) = 1.04139.
9 - 1.04139 = 7.95861.
If you are starting with an acid, you still have to use the -log. The formula for an acid is original chemical pH + (-log(original volume/new volume)).
Diluting the acid will increase the pH and bring it closer to 7. Pure water has a pH value of 7.
Lemon juice has a pH of 3. Diluting it 10:1 will yield:
3 + (-log(1/11)) = 4.04139
If any of you guys really want to be impressed, have a few drinks and dinner with UncleDavy. He'll set you straight............
It is no coincidence that man's best friend cannot talk.
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Re: Diluting chemicals
Originally Posted by
PaulMys
If any of you guys really want to be impressed, have a few drinks and dinner with UncleDavy. He'll set you straight............
You have that right! And fact, I'll buy to learn some of that knowledge he has in his head. thanks so much. tom
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Super Member
I believe in treating everybody with respect, and clean cars. That’s what I believe in.
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