How to Mix IPA for Inspecting Correction Results

[Theraven]

Does this work a gel coat, People use Muriatic acid, bleach, Oxalic acid, and other harsh chemicals/solvents, on boats for cleaning,I know that a lot of these compounds/polishes and waxes ect (marine) can have lots of oils in them. During the detail process is 10-30% IPA strong enough and or worth it. I've experimented with a light solvent/IPA once the dulling effect really shows up on any color gelcoat.

[mike2977]

Great thread, and very useful information on mixing IPA and water to get the % desired.

I plan on using Opti-Coat 2.0 on a freshly re-painted car. After reading many threads here, I'll wait at least 30 days to do the application (although the body shop actually recommends 6 months!)

I've got 95% IPA and will mix it to get the final strength. I've read as low as 10% and as high as 15% in this thread for what I want to accomplish. On new paint with no coating other than the clear coat, following a normal wash (no wax commercial car wash solution,) what would be the best concentration of IPA to use?

And, if I use the wet cloth/dry cloth method of application and immediately wipe, panel by panel, is that the final preparation prior to using Opti-Coat 2.0 or would one wash and dry again?

[sproketser]

Great thread again Mike !

[inDetail]

IPA volume mix. Mathematic flunky. If someone could let me know it would be great. I have a 6 oz spray bottle and 91% IPA. If someone could help me out with the ounces of IPA to put in the bottle it would be a huge help.
Thank you in advance.

[mike2977]

As previously posted in this thread:

For those of you like me, who have a few different size spray bottles, here is the math to figure out your total percentage of IPA in your mix.

X(Y/Z)

Where
X= The percentage of your IPA
Y= Amount of IPA in ounces added to your spray bottle
Z= Total volume of spray bottle in ounces

Let's use Mike's formula as an example. 4oz of 91% IPA in a 32oz spray bottle gives us a total percentage of IPA of 11.3%.
.91(4/32) = .11375 or 11.357%

So if we were to use a smaller, say 22oz bottle we can now figure out how much IPA to add to achieve our target of 10%.
.91(3/22) = .12409 or 12.409%
So, we get 12.4% IPA when we use 3oz of 91% IPA diluted in a 22oz spray bottle.

[inDetail]

Please reply WITHOUT the formula/equation, but with the answer. Here is what I have on hand:
X=91% (percentage of IPA)
Z=6 oz (total ounces of spray bottle)
Y= Need the answer to - #of ounces of H2O to put in spray bottle

Please DO NOT respond with the formula. I am unable to calculate the equation on my own.

[mike2977]

Please reply WITHOUT the formula/equation, but with the answer. Here is what I have on hand:
X=91% (percentage of IPA)
Z=6 oz (total ounces of spray bottle)
Y= Need the answer to - #of ounces of H2O to put in spray bottle

Please DO NOT respond with the formula. I am unable to calculate the equation on my own.

Ok so the formula has to be reworked to provide the answer you are requesting. You really want to know how many ounces of IPA to add to the bottle which will then be filled with water to gain your desired % dilution. And I think we want to use the amount of water in the bottle, not the total volume of the bottle in the calculation, in order to get the proper strength (I could be off since my algebra is a bit rusty. )

I set up a spreadsheet to see how this comes out and think I got it correct:

For different strengths of final solution, it would be:

For your 6 oz bottle,
10% final strength of .91 IPA requires .6 oz of IPA and 5.4 oz of water
12% final strength of .91 IPA requires .7 oz of IPA and 5.3 oz of water
15% final strength of .91 IPA requires .85 oz of IPA and 5.15 oz of water

[mike2977]

Using Excel, here's my recalculation of the original formula, making the Total % IPA (value T) the result of calculating the ratio of IPA (X*Y) divided by the amount of water (W) instead of the volume of the bottle (Z). W=Z-Y. This is followed by the question of what the values would be for a 6 oz bottle:

[IMG][/IMG]

Note that the revised values for the original values are more concentrated since there is less water in the container. A 32 oz container can only hold 4 oz of IPA and 28 oz of water, not 32 oz of water, which caused the mis-calculation in my opinion.

Unfortunately, my algebra is till rusty, so the bottom section was obtained by a quick substitution of values rather than figuring out what the formula might actually be. I'll leave that to the mathematicians out there.

[inDetail]

Thanks Mike. You are a life saver. I Ace'd up to geometry. Flunked everything after that. I'm a visual person. Thank the good lord I'm a printer F/T and a detailer P/T.

[matryx]

I bought some 71% IPA and I have a 32oz bottle. How much ounce of IPA do I need to make around 11% IPA? I'm bad at calculations so if someone can help that would be great.