sg.
11-15-2014, 12:29 AM
This post is motivated by the following
2 microns with 10mL.. my rear end (http://www.autogeekonline.net/forum/pinnacle-wax/86708-pinnacle-paintwork-cleansing-lotion.html#post1187571)Caveat: the "back of the envelope" calculations presented here are based merely on geometry and do _not_ take into account any chemical reactions that might, for example, increase the volume of the chemical being applied; and the calculations do _not_ take into account any intended physical attributes such as that the intention that the chemical merely fill up "voids" in the surface and not really form a complete layer over the surface; etc.
A "typical" size for a sedan in millimeters (mm) (http://automobiles.honda.com/accord-sedan/specifications.aspx): Length (L) 4860, Width (W) 1850, Height (H) 1466, and Height of Sides (S) 815.
The area to be covered (A) is roughly L*W + (2 * (L+W))*S. For the above "typical" numbers, A is roughly 20 square meters.
1 Oz is roughly 30 millimeters or 30 cc or 30/(100*100*100) cubic meters
Getting back to the motivating quote, 1 car with surface of 20 square meters can be covered by 10 mL to a thickness of ((10/(100*100*100))/20)*1000*1000 or 0.5 microns.
Also, if "1 Oz can be used for 4.5 typical cars" then the thickness on each car will be (((30/(100*100*100))/4.5)/20)*1000*1000 micrometers or 0.333 microns.
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2 microns with 10mL.. my rear end (http://www.autogeekonline.net/forum/pinnacle-wax/86708-pinnacle-paintwork-cleansing-lotion.html#post1187571)Caveat: the "back of the envelope" calculations presented here are based merely on geometry and do _not_ take into account any chemical reactions that might, for example, increase the volume of the chemical being applied; and the calculations do _not_ take into account any intended physical attributes such as that the intention that the chemical merely fill up "voids" in the surface and not really form a complete layer over the surface; etc.
A "typical" size for a sedan in millimeters (mm) (http://automobiles.honda.com/accord-sedan/specifications.aspx): Length (L) 4860, Width (W) 1850, Height (H) 1466, and Height of Sides (S) 815.
The area to be covered (A) is roughly L*W + (2 * (L+W))*S. For the above "typical" numbers, A is roughly 20 square meters.
1 Oz is roughly 30 millimeters or 30 cc or 30/(100*100*100) cubic meters
Getting back to the motivating quote, 1 car with surface of 20 square meters can be covered by 10 mL to a thickness of ((10/(100*100*100))/20)*1000*1000 or 0.5 microns.
Also, if "1 Oz can be used for 4.5 typical cars" then the thickness on each car will be (((30/(100*100*100))/4.5)/20)*1000*1000 micrometers or 0.333 microns.
.