Diluting chemicals

[UncleDavy]

You have to use the -log to get a positive value for that part of the equation. The log(1/11) = -1.04139. The -log(1/11) = 1.04139.
9 - 1.04139 = 7.95861.
If you are starting with an acid, you still have to use the -log. The formula for an acid is original chemical pH + (-log(original volume/new volume)).
Diluting the acid will increase the pH and bring it closer to 7. Pure water has a pH value of 7.
Lemon juice has a pH of 3. Diluting it 10:1 will yield:
3 + (-log(1/11)) = 4.04139

[PaulMys]

You have to use the -log to get a positive value for that part of the equation. The log(1/11) = -1.04139. The -log(1/11) = 1.04139.
9 - 1.04139 = 7.95861.
If you are starting with an acid, you still have to use the -log. The formula for an acid is original chemical pH + (-log(original volume/new volume)).
Diluting the acid will increase the pH and bring it closer to 7. Pure water has a pH value of 7.
Lemon juice has a pH of 3. Diluting it 10:1 will yield:
3 + (-log(1/11)) = 4.04139

If any of you guys really want to be impressed, have a few drinks and dinner with UncleDavy. He'll set you straight............

[Jayfro]

If any of you guys really want to be impressed, have a few drinks and dinner with UncleDavy. He'll set you straight............

I’ve taken 3 sips of a Dos Equis Especial cerveza...after reading that..:I think I need a few more sips...or gulps!


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[Hooked Up]

If any of you guys really want to be impressed, have a few drinks and dinner with UncleDavy. He'll set you straight............

You have that right! And fact, I'll buy to learn some of that knowledge he has in his head. thanks so much. tom

[UncleDavy]

The drinks are on me.